数学
高校生

分かる方いらっしゃいますか

Q1. 1 個のさいころを180回投げるとき, 1の目が出る ²) 6 回数を X とすると, Xは二項分布B 180, うから、Xの平均と標準偏差のは, 1 m= 180 x Z == 6 ここで,n=180は十分に大きいから, X-m X-30 = 1 5 30, o = 180 x × V 6 6 = - に従 LO 5 0 5 は,標準正規分布N (0, 1) に従うとみなしてよい。 このとき, 1個のさいころを180回投げるとき,1の目が 35回以上出る確率は 【1】である。 小数第4位まで求 めなさい。 必要があれば, 教科書 153Pの正規分布表を用いなさい。
STATUS FRED PERRA IZANG 22222 =23EE REG 0.0 0.1 0.3 0.5 0.9 2.7 1.3 1.6 .00 .01 正規分布表 3.6 .49984 3.7 .49989 .02 3.8 49993 .03 .32121 .34614 .04 2.05 2.06 .37286 .39251 .36864 .37076 .40988 .37493 .37698 .37900 .38100 .38298 .38877 .39065 39435 .39617 .39796 39973.40147 40658 .40824 41149 .41309 41466 41621 .41774 .42220 .42364 .42507 .42647 .42786 .42922 .43056 .43189 .43574 .43699 .43822 .43943 .44062 .44179 44295 44408 44738 .44845 .44950 45053 .45154 .45254 .45352 .45449 .45818 .45907 .45994.46080 46164 .46246 46327 .46638 .46712 .46784 .46856 .46926 .46995 .47062 47128 47193 .47257 .47320 .47381 .47441 .47500 .47558 .47615 47670 20 .47725 .47778 47831 .47882 .47932 .47982 48030 .48077 48124 .48169 .36433 .36650 .38493 .38686 .40320 .40490 .41924 .42073 .43319 .43448 .44520 44630 .45543 .45637 .45728 1.8 .46407 .46485.46562 49995 49995 49996 49996 2.07 00000 .00399 .00798 .01197 .01595 .01994 .02392 02790 .03188 .03586 07142 .07535 03983 .04380 .04776 .05172 .05567 .05962 06356 06749 .07926.08317 .08706 .09095 09483 09871 .10257 .10642 11791 .12172 .12552 .12930 .13307 .13683 14058 .11026 .11409 .14431 .15542 .15910 .16276 .16640 .17003 .17364 .17724 .14803 15173 .18082.18439 .18793 .19146.19497 .19847 .20194 .20540 .20884 .21226 .21566 .21904 .22240 .22575 .22907 .23237 .23565 .23891 .24215 .24537 .24857 .25175 .25490 .25804 .26115 .26424 .26730 27035 .27337 .27637 .27935 .28230 .28524 .29673 .29955 .30234 .30511 .30785 .31057 .31327 .32381 .32639 .32894 .33147 .33398 .33646 .33891 .35083 .35314 .35543 .35769 .35993 36214 .28814 .29103 .29389 .31594 .31859 .34134 .34375 .34850 0 .08 2 .48214 48257 .48300 .48341 .48382 .48422 .48461 48500 48537 .48574 2.2 .48610 48645 .48679 .48713 .48745 48778 .48809 .48840 .48870 .48899 .49086 49111 .49134 .49158 .48928.48956 48983 .49010 .49036 .49061 2.4 .49180 .49202.49224.49245 .49266 49286 .49305 .49324 49343 49361 2.5 .49379 .49396 49413 49430 .49446.49461 .49477 .49653 .49664 2.8 .49744.49752 2.9 .49813 49819 .49492 49506 .49520 26 .49534 49547 49560 .49573.49585 .49598 49609 49621 49632 .49643 .49674 .49683 49693 .49702 .49711 49720 49728 .49736 .49760.49767 49774 .49781 .49788 49795 49801 49807 49825 49831 .49836 .49841 .49846 .49851 .49856 .49861 3.0 .49865 49869 .49874 .49878 .49882.49886 .49889 49893 .49897 49900 .49913 .49916 49918 .49921 49924 .49926.49929 .49938 49940 .49942 49944 49946 49948 49950 3.3 .49952 49953 49955 .49957.49958 .49960 .49961 .49962 .49964 49965 3.4 49966 49968 49969.4997049971 .49972 49973 49974 .49975 .49976 3.5 49977 .49978 .49978 49979 .49980 .49981 .49981 .49982 .49983 .49983 3.1 .49903.49906 .49910 .49931 .49934.49936 .09 49985 49985 49986 49986 .49987 49987 49988 49988 .49989 .49992 49990 49990 49990 .49991 49991 49992 49992 49992 .49993 49993 49994.49994 49994 49994 49995 49995 49995 49996 49996 49996 49997 49997 .49996
標本平均の分布

回答

Xは1の目の出る回数なので、
X≧35 とおくことができるから、Zに変換して
Z≧(35-30)/5
→ Z≧1
P(Z≧1)
=0.5-P(0≦Z≦1)
=0.5-0.1587
=0.3413

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