ページ1:

Hidrolisis Garam
AK HCC HBr, HI, HSO4 HNO3 HClou
AGL = CH3COOH, HF, H₂ CO3, HCN, H₂S
BK = NaOH, KOH, Ba(OH)₂, Ca(OH)₂
BL = NH3 atau NH₂OH, Al(OH)3
1.) Tentukan (asam/basa/netral)
a. Nas Na* + St
NaOH HS
BK
AL
Na +H₂O tdk ada reaksi
SH₂O₂S+20H¯
bersifat baso
b. (NH4)2SO4 2NH₁ +504
PH = -log [H]
=-109 [√5x105]
=5-109√5
=
4.) Hitung pH dan 100 mL larutan
(CH,COO) Bu 0,01 M. (K₁ = 105)
(CH3COOH)₂ Ba→2CH, COOH + Bo²+
0.01M
[NH4OH H₁₂SO4 [OH]-\ K
0,02M
0,01M
AL
BK
ka × [A]
10
10-5
×2×102
BL AK
2NH4+H202NH4OH+2+*
Soy +H20
bersifat asam
bulk ada reaksi
c. K₂SOy 2k +502
KOH H₂SO
BK AK
2K + H₂0 tdk ada reaks
So++20tak ada reaksi
bersifat netra
2) Hitung pH larutan CaSO4, 0,02M!
"Casoy Ca++ 50
BK AK
bersifat netral krn BK + AK
dengan PH-7
√√2 × 105.5
PH-14-POH
POH = -109 [OH]
=-109√2x1055]
=5.5-10912
PH = 14-5,5-109√2
= 8.5+109 √2
5.) Hitung PH larutan NH, NO, 01 M
(kb= 10-5) din tentukan Sifatnya?
3) Hitung pH com langban MS01 NHNO3 NHA NÓI
0.5 M dan kb-1×10³ !
MgSoy Mg++ SO²
→
BL
[MgSOy]= 0,5 M
F = 100 mL
[H]= k[B]
kb
√5 x 10-5
=
AK
kb=1×105
10-1
10-5
[05]
(109 x 5×10
-10
BL AK
WHY NO₂ = NH4+ NO,
Ul
Hot
10°5
OL
xx/07
PH = -109 [1x105]
+109[1x103]
=5
O
10% 10
@Belo jarer
10-0
103

ページ2:

Hidrolisis Garan
6.) NH4OH = 0,01 M
Ha =0,0M
=25mL
=25 ML
16=5×1010
Tentukan pH dn sifatnya!
ELS
In NH4OH = 0,01 × 25 = 0,25 mmol
He
=0,01 x 25=0,25 mmol
-
NH4OH + H NH4Cl + H₂O
0,25 0,25
r 0.25 0,25
S
NH4025 mmol
925
0,25 mmo
M=
0,25 mmol
=
0.25
-- 0,005 M
total
25+25 mL
50 ML
NHyce NH4+ + a
0,005 0.005
[B] = 0,005
menghitung PH
=
-log [+]
[H+] = \[B]
-
70-14
√5x100 x 5 × 10-3
5×10-17
5×1070
=√10%
103,5
Pl+=-109 [103,6]
=3.5
@Belo jarer