Mathematics
Undergraduate
11が出来なくて、教えて欲しいです🙏
よろしくお願いします。
次の式を簡単にせよ。
(1) cosの9二 ces(
々
9+テ
(2⑫) sin (の十る) cos(9+
) 十cos(の9十z) +cos(
9 NM
の
3) 十sin (0 ー9)cos(-の
2
11|
間MIDIHNIDIOI放7 0人MR
①⑪ cw(+が)=cs(+す)+<| =-ce(9+引=ang
よって (与式)ニcosの(一 MAUUSGO34)Hm9ニ 0
(2) (与式)=(-sin の)・(一sin の)二cosの・cosの
=sin 9十cos?9ニ1
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