✨ Best Answer ✨
(dy/dx)sinx=(cosx-sinx)y
(1/y)dy=(sinx/cosx-sinx)dx
で変数分離形となる
計算は適当なんで。要は変数分離形
ありがとうございます
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✨ Best Answer ✨
(dy/dx)sinx=(cosx-sinx)y
(1/y)dy=(sinx/cosx-sinx)dx
で変数分離形となる
計算は適当なんで。要は変数分離形
ありがとうございます
Users viewing this question
are also looking at these questions 😉
(1/y)dy=(cosx/sinx-1)dxとなりません？