(sin³ fog (x) ->
f(x) = 203, g(x)=sink
-
(fog)'= 3 sin 7. cos
①√tank - Togex - f(x)=√x, gcx1 = tank
(fog)' = + (tank) -
C05270
(og (sinkt = fog(x) → fext = log (21, gem = sink.
(fog)'= sinx cos x = tank
A
sin²x = fog (x)
→
⑦ex = fog(x)
f(x) = g(x = sink
(fog) = 5%
fix=ex, g(x) = x²
r
(fog) = ex. 2x